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1.5x^2-72=0
a = 1.5; b = 0; c = -72;
Δ = b2-4ac
Δ = 02-4·1.5·(-72)
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{3}}{2*1.5}=\frac{0-12\sqrt{3}}{3} =-\frac{12\sqrt{3}}{3} =-4\sqrt{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{3}}{2*1.5}=\frac{0+12\sqrt{3}}{3} =\frac{12\sqrt{3}}{3} =4\sqrt{3} $
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